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Original: 11/3/2007 12:26 PM
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Saturday, November 03, 2007

 

HELP~~!!! [Maths]

1.Find the centre and equation of circle if it touches the line x-6=0 and y-axis with y-intercept =4

Centre=(3,4)
Radius=3
Equation of circle:
(x-3)^2 + (y-4)^2 =9

2)Find the equations of circles which pass through (2,-1) and touch both axes

.....
....
....
a^2+6a-5 = 0
a=-3+√14,-3-√14 (rej.)
The required equations is x^2 +y^2 -2(-3+√14)x+2(-3+√14)y -(-3+√14)^2=0

 

 

 

 Posted 11/3/2007 12:26 PM - 1 View - 0 eProps - 0 comments

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